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C++ - "multiplying two numbers and giving the square root" in Programming Languages


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Old 03-02-2004   #1
.... ..o
 
Default Re: multiplying two numbers and giving the square root

cplusplus <cplusplus@linux.local> wrote in
newsan.2006.06.14.19.57.23.360438@linux.local:

> int number1,number2, product;


should be
int number1,number2, product, root = 0;
 
Old 03-03-2004   #2
.... ..hmi..
 
Default Re: multiplying two numbers and giving the square root

On Wed, 14 Jun 2006 12:57:24 -0700, cplusplus wrote:

> Hello, I have newbie question.


[snip]

> here is the error I'm getting:


> combine.cc: In function `int main()':
> combine.cc:16: error: `root' undeclared (first use this function)


It's quite simple, really. Compiler error messages are not always clear,
but this one is. If you become a programmer, you will be spending a lot of
time deciphering what the error message means in terms of your code, so
it's best to start right away! The problem here is that you have not
declared your root variable. In your first example program, you have

> double intOne; // use double for real numbers


You have no such declaration for root in the combined program.

John's answer was close, but would give you an integral root, which would
not produce the desired answer (it would give 6 as the root of 6 * 7).

--
Greg Schmidt gregs@trawna.com
Trawna Publications http://www.trawna.com/
 
Old 06-14-2006   #3
..l..pl..
 
Default multiplying two numbers and giving the square root

Hello, I have newbie question.
I'm stuck on this current ***ignment.

Write a program that prompts the user for two integer values,
p***es the values to a function where they are multiplied
together and the square root of the product is returned and
displayed for the user. The function should return a double.
Hint: If you multiply an integer by 1.0 the result will be a
double. For example:

Enter an integer: 7
Enter another integer: 6
The square root of 7 times 6 = 6.48074

--
ok, so what I did was created a program that would get the
sqaure root of a number, and then created another one that multipled
2 numbers. Here is the source for the square root:

#include <iostream>
#include <cmath>
using namespace std;

int main()
{
double intOne; // use double for real numbers

cout << "Enter an integer:\n";
cin >> intOne;
double side; // create another variable
side = sqrt( intOne ); // call function, ***ign return value
cout << "The square root is " << side;
cout << " \n";

return 0;
}

here is the source for multiplying the two integers:

#include <iostream>
using namespace std;


int main()
{
int number1,number2, product;
cout << "Enter a number: ";
cin >> number1;
cout << "Enter another number: ";
cin >> number2;
product = number1 * number2;
cout << "The product of " << number1 <<" and "<< number2 << " is " << product <<"\n";
return 0;
}

I tried to combine the two together using this code:

#include <iostream>
using namespace std;


int main()
{
int number1,number2, product;
cout << "Enter a number: ";
cin >> number1;
cout << "Enter another number: ";
cin >> number2;
product = number1 * number2;
cout << "The product of " << number1 <<" and "<< number2 << " is " << product <<"\n";
root = sqrt( product );
cout << "The square root is " << root <<"\n";

return 0;
}

here is the error I'm getting:

combine.cc: In function `int main()':
combine.cc:16: error: `root' undeclared (first use this function)
combine.cc:16: error: (Each undeclared identifier is reported only once for
each function it appears in.)
combine.cc:16: error: call of overloaded `sqrt(int&)' is ambiguous
/usr/include/bits/mathcalls.h:157: error: candidates are: double sqrt(double)
/usr/include/g++/cmath:550: error: long double std::sqrt(long
double)
/usr/include/g++/cmath:546: error: float std::sqrt(float)

I'm new to this language and any help would be greatly
appreciated. It would be great if someone could point
me in the right direction.
Thanks a bunch,

--Cameron
 

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